Posts: 2
Threads: 1
Joined: Jun 2010
06/16/2010, 02:32 PM
(This post was last modified: 06/16/2010, 02:37 PM by brangelito.)
The solution to the equation:
Seems to be given by:
Put c=e, and you get the Lambert W-function.
Is this already known?
Posts: 1,631
Threads: 107
Joined: Aug 2007
06/16/2010, 02:50 PM
(This post was last modified: 06/16/2010, 02:52 PM by bo198214.)
(06/16/2010, 02:32 PM)brangelito Wrote: The solution to the equation:
Seems to be given by:
You mean 1/c instead of 1/x?!
The limit \( x=\lim_{n\to\infty} \frac{1}{c}[4]n \) satisfies the equation
\( \left(\frac{1}{c}\right)^x = x \) (if I add another \( \frac{1}{c} \) at the bottom of the infinite tower, the value must stay the same).
This equation is equivalent to your equation above:
\( 1=c^x x \)