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tommy1729 · 02/03/2017, 01:27 PM

If the base b is sufficiently Large then log_b(z) = z has no solution right ?

So how does that work out for fixpoint methods ?

JmsNxn · 02/03/2017, 08:00 PM

Well \( b^z = z \) has infinitely many solutions, so for some branch of \( \log_b \) there is always a fixed point.

tommy1729 · 02/05/2017, 09:42 AM

It seems the fixpoints imaginary value Goes down fast enough to stay in the strip. Nice.

Concluded from Lambert W.

Regards

Tommy1729

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