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When Does \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x\) Equal \(\frac12\)? - Printable Version +- Tetration Forum (https://tetrationforum.org) +-- Forum: Tetration and Related Topics (https://tetrationforum.org/forumdisplay.php?fid=1) +--- Forum: Mathematical and General Discussion (https://tetrationforum.org/forumdisplay.php?fid=3) +--- Thread: When Does \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x\) Equal \(\frac12\)? (/showthread.php?tid=1668) |
When Does \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x\) Equal \(\frac12\)? - Catullus - 10/31/2022 With the linear approximation of tetration, \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x=\frac12\). For what complex base(s) does \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x\) equal \(\frac12\) with the the analytic continuation of the Kneser method? Also, for what complex base(s) does \(\text{sexp}(-\frac12)\) equal \(\frac12\) with the same method of tetration? |