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+--- Thread: Tommy-Gottfried divisions. (/showthread.php?tid=1026)
Tommy-Gottfried divisions. - tommy1729 - 10/09/2015
If we divide exp by 1 + x we get another Taylor that starts with 1.
Exp(x)/(1+x) = 1 + a x^2 + ...
We could repeat by dividing by (1 + a x^2).
This results in Gottfried's pxp(x) and " dream of a sequence ".
Notice it gives a product expansion that suggests zero's for exp.
" fake zero's " sort a speak.
Im considering analogues.
Start with exp(x) / (1 + x + x^2/2) maybe ?
I think I recall Some impossibility or critisism about such variants. But I forgot what that was.
Regards
Tommy1729